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2. The correct answer is nine. In your notes draw ten monomers
linked together by a single line. How many single lines do you need to
break? The answer will always be one less than the number of monomers
linked together.
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3. XXXX-OH + HO-XXXXXX-OH + HO-XX ----------------------->
reactants (3 monomers)
XXXX-O-XXXXXX-O-XX + 2 HOH
products (1 polymer)
water
Note: Two waters were split out (one less water than the number of
monomers)
Write this equation in your notes.
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4. XXXX-O-XX-O-XX-O-YYYYN + 3 HOH
-------->
reactants (1 polymer)
water
XXXX-OH + HO-XX-OH + HO-XX -OH
+ OH-YYYYN
products (4 monomers)
Note: Three water were required and four monomers were split out.
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