1. The correct answer is four. The answer will always be one less than the number of monomers present in the polymer.  You will cleave water from the first, second, third and fourth monomer. The fifth monomer of the chain does not have anything attached to it.

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2. The correct answer is  nine. In your notes draw ten monomers linked together by a single line. How many single lines do you need to break?  The answer will always be one less than the number of monomers linked together.

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3. XXXX-OH  + HO-XXXXXX-OH  +  HO-XX  ----------------------->
              reactants (3 monomers)

                                                       XXXX-O-XXXXXX-O-XX    +    2 HOH
                                                            products (1 polymer)               water
Note: Two waters were split out (one less water than the number of monomers)

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4. XXXX-O-XX-O-XX-O-YYYYN   +   3 HOH    -------->
       reactants (1 polymer)                       water

                                            XXXX-OH  +  HO-XX-OH   +   HO-XX -OH   +  OH-YYYYN
                                                              products (4 monomers)
 
Note: Three water were required and four monomers were split out.

Write this equation in your notes.

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