Physics 102 Homework set 11 Solutions L. Weinstein Exercises: ---------- 31.34: The slower electron has the longer wavelength. lambda = h/p = h/mv. The larger v is, the smaller lambda is. 31.47: Heisenberg's uncertainty principle does not apply here because it is possible to devise a way to measure air pressure without letting any air escape. It also does not apply here because it applies to the simultaneous measurement of two quantities such as position and momentum or energy and time. 32.2: A blue photon has a higher frequency and hence a higher energy than a red one. Therefore it results from a greater energy transition. 32.8: If an electron in a hydrogen atom obeyed classical mechanics, then hydrogen would have a continuous spectrum. The line spectrum occurs because electrons can only occupy specific discrete orbits so that there are only certain energy differences between orbits. These energy differences are the allowed energies of emitted photons. If the electrons obeyed classical mechanics, then they could occupy any orbit with any energy. 32.14: The photoelectric effect is best explained by the particle nature of the electron. Photons knock out single electrons. You cannot knock out a fraction of an electron. The discrete levels in the Bohr model are best explained by the wave nature of electrons. The electron orbits correspond to standing waves of the electron in a circle around the nucleus. 33.2: X-rays and gama rays are both electromagnetic radiation. 33.4: The atoms of the radioactive material are unstable. When they decay, they release energy. Part of that energy is converted to the thermal energy of the sample. 33.8: A gamma ray is uncharged and will not be deflected by the electric field. An alpha particle has a positive charge and will be deflected in the direction of the field lines. A beta particle has a negative charge and will be deflected in the opposite direction to the field lines. 33.16: The repulsion comes from the electric force between the two protons. The attraction comes from the nuclear force between the two protons. 33.20: A positively charged hydrogen atom is a proton. A neutral H atom has one proton and one electron. To make it positively charged, you must remove the electron. 33.22: Inverse square law: If it registers 360 counts per minute (cpm) at a distance of 1 m, then it will register 360/2^2 = 90 cpm at a distance of 2 m and it will register 360/3^2 = 40 cpm at a distance of 3 m. Problems: -------------------- 33.2: In order to decrease from 160 counts per minute (cpm) to 10 cpm, it must have halved four times (160 -> 80 -> 40 -> 20 -> 10). Therefore, four half-lives have elapsed in 8 hours. Therefore, the half life of the material is 2 hours. Estimation: --------------------- We are about 70 km from Surrey. This means that the neutrinos from Surry are spread out over the surface of a sphere of radius 70 km. This sphere has area A = 4 pi r^2 = 4 * 3 * (7*10^4 m)^2 = 6*10^10 m^2. The surface area of the front of my body is about 1 m^2 (about 2 m tall by 0.5 m wide). This means that the number of neutrinos passing through my body from Surry every second is: N = 4*10^20 neutrinos/second * 1 m^2 / 6*10^10 m^2 = 6*10^9 neutrinos/second. Wow! That's a lot!